5(2t-2)+5t=-35-10t

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Solution for 5(2t-2)+5t=-35-10t equation:



5(2t-2)+5t=-35-10t
We move all terms to the left:
5(2t-2)+5t-(-35-10t)=0
We add all the numbers together, and all the variables
5(2t-2)+5t-(-10t-35)=0
We add all the numbers together, and all the variables
5t+5(2t-2)-(-10t-35)=0
We multiply parentheses
5t+10t-(-10t-35)-10=0
We get rid of parentheses
5t+10t+10t+35-10=0
We add all the numbers together, and all the variables
25t+25=0
We move all terms containing t to the left, all other terms to the right
25t=-25
t=-25/25
t=-1

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