5(2t-3)=2(4t+3)-10

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Solution for 5(2t-3)=2(4t+3)-10 equation: 



5(2t-3)=2(4t+3)-10

We move all terms to the left:

5(2t-3)-(2(4t+3)-10)=0

We multiply parentheses

10t-(2(4t+3)-10)-15=0



We calculate terms in parentheses: -(2(4t+3)-10), so:

2(4t+3)-10

We multiply parentheses

8t+6-10

We add all the numbers together, and all the variables

8t-4

Back to the equation:

-(8t-4)



We get rid of parentheses

10t-8t+4-15=0

We add all the numbers together, and all the variables

2t-11=0

We move all terms containing t to the left, all other terms to the right

2t=11

t=11/2

t=5+1/2

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