5(2t-3)=7(I-2)+16

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Solution for 5(2t-3)=7(I-2)+16 equation: 


Simplifying
5(2t + -3) = 7(I + -2) + 16

Reorder the terms:
5(-3 + 2t) = 7(I + -2) + 16
(-3 * 5 + 2t * 5) = 7(I + -2) + 16
(-15 + 10t) = 7(I + -2) + 16

Reorder the terms:
-15 + 10t = 7(-2 + I) + 16
-15 + 10t = (-2 * 7 + I * 7) + 16
-15 + 10t = (-14 + 7I) + 16

Reorder the terms:
-15 + 10t = -14 + 16 + 7I

Combine like terms: -14 + 16 = 2
-15 + 10t = 2 + 7I

Solving
-15 + 10t = 2 + 7I

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 10t = 2 + 15 + 7I

Combine like terms: -15 + 15 = 0
0 + 10t = 2 + 15 + 7I
10t = 2 + 15 + 7I

Combine like terms: 2 + 15 = 17
10t = 17 + 7I

Divide each side by '10'.
t = 1.7 + 0.7I

Simplifying
t = 1.7 + 0.7I

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