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5(2v+3)-2=12v+12=2v
We move all terms to the left:
5(2v+3)-2-(12v+12)=0
We multiply parentheses
10v-(12v+12)+15-2=0
We get rid of parentheses
10v-12v-12+15-2=0
We add all the numbers together, and all the variables
-2v+1=0
We move all terms containing v to the left, all other terms to the right
-2v=-1
v=-1/-2
v=1/2
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