5(2w+1)=7w-4(7+w)

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Solution for 5(2w+1)=7w-4(7+w) equation:



5(2w+1)=7w-4(7+w)
We move all terms to the left:
5(2w+1)-(7w-4(7+w))=0
We add all the numbers together, and all the variables
5(2w+1)-(7w-4(w+7))=0
We multiply parentheses
10w-(7w-4(w+7))+5=0
We calculate terms in parentheses: -(7w-4(w+7)), so:
7w-4(w+7)
We multiply parentheses
7w-4w-28
We add all the numbers together, and all the variables
3w-28
Back to the equation:
-(3w-28)
We get rid of parentheses
10w-3w+28+5=0
We add all the numbers together, and all the variables
7w+33=0
We move all terms containing w to the left, all other terms to the right
7w=-33
w=-33/7
w=-4+5/7

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