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5(2x+-1)=2(x+3)
We move all terms to the left:
5(2x+-1)-(2(x+3))=0
We add all the numbers together, and all the variables
5(2x-1)-(2(x+3))=0
We multiply parentheses
10x-(2(x+3))-5=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
10x-2x-6-5=0
We add all the numbers together, and all the variables
8x-11=0
We move all terms containing x to the left, all other terms to the right
8x=11
x=11/8
x=1+3/8
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