5(2x+1)+10(3x-10)=20

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Solution for 5(2x+1)+10(3x-10)=20 equation:


Simplifying
5(2x + 1) + 10(3x + -10) = 20

Reorder the terms:
5(1 + 2x) + 10(3x + -10) = 20
(1 * 5 + 2x * 5) + 10(3x + -10) = 20
(5 + 10x) + 10(3x + -10) = 20

Reorder the terms:
5 + 10x + 10(-10 + 3x) = 20
5 + 10x + (-10 * 10 + 3x * 10) = 20
5 + 10x + (-100 + 30x) = 20

Reorder the terms:
5 + -100 + 10x + 30x = 20

Combine like terms: 5 + -100 = -95
-95 + 10x + 30x = 20

Combine like terms: 10x + 30x = 40x
-95 + 40x = 20

Solving
-95 + 40x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '95' to each side of the equation.
-95 + 95 + 40x = 20 + 95

Combine like terms: -95 + 95 = 0
0 + 40x = 20 + 95
40x = 20 + 95

Combine like terms: 20 + 95 = 115
40x = 115

Divide each side by '40'.
x = 2.875

Simplifying
x = 2.875

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