5(2x+1)+3(2x+4)=4(4x+7)

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Solution for 5(2x+1)+3(2x+4)=4(4x+7) equation:



5(2x+1)+3(2x+4)=4(4x+7)
We move all terms to the left:
5(2x+1)+3(2x+4)-(4(4x+7))=0
We multiply parentheses
10x+6x-(4(4x+7))+5+12=0
We calculate terms in parentheses: -(4(4x+7)), so:
4(4x+7)
We multiply parentheses
16x+28
Back to the equation:
-(16x+28)
We add all the numbers together, and all the variables
16x-(16x+28)+17=0
We get rid of parentheses
16x-16x-28+17=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation

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