5(2x+1)+3(4-+2)=33

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Solution for 5(2x+1)+3(4-+2)=33 equation: 



5(2x+1)+3(4-+2)=33

We move all terms to the left:

5(2x+1)+3(4-+2)-(33)=0

determiningTheFunctionDomain
5(2x+1)-33+3(4-+2)=0

We add all the numbers together, and all the variables

5(2x+1)-33+30=0

We add all the numbers together, and all the variables

5(2x+1)-3=0

We multiply parentheses

10x+5-3=0

We add all the numbers together, and all the variables

10x+2=0

We move all terms containing x to the left, all other terms to the right

10x=-2

x=-2/10

x=-1/5

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