5(2x+1)+3(4x+2)=33

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Solution for 5(2x+1)+3(4x+2)=33 equation: 



5(2x+1)+3(4x+2)=33

We move all terms to the left:

5(2x+1)+3(4x+2)-(33)=0

We multiply parentheses

10x+12x+5+6-33=0

We add all the numbers together, and all the variables

22x-22=0

We move all terms containing x to the left, all other terms to the right

22x=22

x=22/22

x=1

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