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5(2x+1)+3/9=2
We move all terms to the left:
5(2x+1)+3/9-(2)=0
determiningTheFunctionDomain 5(2x+1)-2+3/9=0
We multiply parentheses
10x+5-2+3/9=0
We multiply all the terms by the denominator
10x*9+3+5*9-2*9=0
We add all the numbers together, and all the variables
10x*9+30=0
Wy multiply elements
90x+30=0
We move all terms containing x to the left, all other terms to the right
90x=-30
x=-30/90
x=-1/3
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