5(2x+1)+4=6(3x+2)7

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Solution for 5(2x+1)+4=6(3x+2)7 equation: 



5(2x+1)+4=6(3x+2)7

We move all terms to the left:

5(2x+1)+4-(6(3x+2)7)=0

We multiply parentheses

10x-(6(3x+2)7)+5+4=0



We calculate terms in parentheses: -(6(3x+2)7), so:

6(3x+2)7

We multiply parentheses

126x+84

Back to the equation:

-(126x+84)



We add all the numbers together, and all the variables

10x-(126x+84)+9=0

We get rid of parentheses

10x-126x-84+9=0

We add all the numbers together, and all the variables

-116x-75=0

We move all terms containing x to the left, all other terms to the right

-116x=75

x=75/-116

x=-75/116

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