5(2x+1)-2(5x+2)=8(x-4)

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Solution for 5(2x+1)-2(5x+2)=8(x-4) equation: 



5(2x+1)-2(5x+2)=8(x-4)

We move all terms to the left:

5(2x+1)-2(5x+2)-(8(x-4))=0

We multiply parentheses

10x-10x-(8(x-4))+5-4=0



We calculate terms in parentheses: -(8(x-4)), so:

8(x-4)

We multiply parentheses

8x-32

Back to the equation:

-(8x-32)



We add all the numbers together, and all the variables

-(8x-32)+1=0

We get rid of parentheses

-8x+32+1=0

We add all the numbers together, and all the variables

-8x+33=0

We move all terms containing x to the left, all other terms to the right

-8x=-33

x=-33/-8

x=4+1/8

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