5(2x+1)-3=4x+4(x-8)

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Solution for 5(2x+1)-3=4x+4(x-8) equation: 



5(2x+1)-3=4x+4(x-8)

We move all terms to the left:

5(2x+1)-3-(4x+4(x-8))=0

We multiply parentheses

10x-(4x+4(x-8))+5-3=0



We calculate terms in parentheses: -(4x+4(x-8)), so:

4x+4(x-8)

We multiply parentheses

4x+4x-32

We add all the numbers together, and all the variables

8x-32

Back to the equation:

-(8x-32)



We add all the numbers together, and all the variables

10x-(8x-32)+2=0

We get rid of parentheses

10x-8x+32+2=0

We add all the numbers together, and all the variables

2x+34=0

We move all terms containing x to the left, all other terms to the right

2x=-34

x=-34/2

x=-17

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