5(2x+1)-4(3x-2)+8=3(x-9)+10

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Solution for 5(2x+1)-4(3x-2)+8=3(x-9)+10 equation: 



5(2x+1)-4(3x-2)+8=3(x-9)+10

We move all terms to the left:

5(2x+1)-4(3x-2)+8-(3(x-9)+10)=0

We multiply parentheses

10x-12x-(3(x-9)+10)+5+8+8=0



We calculate terms in parentheses: -(3(x-9)+10), so:

3(x-9)+10

We multiply parentheses

3x-27+10

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We add all the numbers together, and all the variables

-2x-(3x-17)+21=0

We get rid of parentheses

-2x-3x+17+21=0

We add all the numbers together, and all the variables

-5x+38=0

We move all terms containing x to the left, all other terms to the right

-5x=-38

x=-38/-5

x=7+3/5

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