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5(2x+1)-7x=-4(x-5)
We move all terms to the left:
5(2x+1)-7x-(-4(x-5))=0
We add all the numbers together, and all the variables
-7x+5(2x+1)-(-4(x-5))=0
We multiply parentheses
-7x+10x-(-4(x-5))+5=0
We calculate terms in parentheses: -(-4(x-5)), so:We add all the numbers together, and all the variables
-4(x-5)
We multiply parentheses
-4x+20
Back to the equation:
-(-4x+20)
3x-(-4x+20)+5=0
We get rid of parentheses
3x+4x-20+5=0
We add all the numbers together, and all the variables
7x-15=0
We move all terms containing x to the left, all other terms to the right
7x=15
x=15/7
x=2+1/7
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