5(2x+1)=(3x+12)-5

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Solution for 5(2x+1)=(3x+12)-5 equation: 



5(2x+1)=(3x+12)-5

We move all terms to the left:

5(2x+1)-((3x+12)-5)=0

We multiply parentheses

10x-((3x+12)-5)+5=0



We calculate terms in parentheses: -((3x+12)-5), so:

(3x+12)-5

We get rid of parentheses

3x+12-5

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

10x-3x-7+5=0

We add all the numbers together, and all the variables

7x-2=0

We move all terms containing x to the left, all other terms to the right

7x=2

x=2/7

x=2/7

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