5(2x+1)=(3x+4)-5

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Solution for 5(2x+1)=(3x+4)-5 equation: 



5(2x+1)=(3x+4)-5

We move all terms to the left:

5(2x+1)-((3x+4)-5)=0

We multiply parentheses

10x-((3x+4)-5)+5=0



We calculate terms in parentheses: -((3x+4)-5), so:

(3x+4)-5

We get rid of parentheses

3x+4-5

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We get rid of parentheses

10x-3x+1+5=0

We add all the numbers together, and all the variables

7x+6=0

We move all terms containing x to the left, all other terms to the right

7x=-6

x=-6/7

x=-6/7

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