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5(2x+1)=-(x-3)-4
We move all terms to the left:
5(2x+1)-(-(x-3)-4)=0
We multiply parentheses
10x-(-(x-3)-4)+5=0
We calculate terms in parentheses: -(-(x-3)-4), so:We get rid of parentheses
-(x-3)-4
We get rid of parentheses
-x+3-4
We add all the numbers together, and all the variables
-1x-1
Back to the equation:
-(-1x-1)
10x+1x+1+5=0
We add all the numbers together, and all the variables
11x+6=0
We move all terms containing x to the left, all other terms to the right
11x=-6
x=-6/11
x=-6/11
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