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5(2x+1)=-3(2x-2)
We move all terms to the left:
5(2x+1)-(-3(2x-2))=0
We multiply parentheses
10x-(-3(2x-2))+5=0
We calculate terms in parentheses: -(-3(2x-2)), so:We get rid of parentheses
-3(2x-2)
We multiply parentheses
-6x+6
Back to the equation:
-(-6x+6)
10x+6x-6+5=0
We add all the numbers together, and all the variables
16x-1=0
We move all terms containing x to the left, all other terms to the right
16x=1
x=1/16
x=1/16
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