5(2x+1)=1/2(10x+1)+5

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Solution for 5(2x+1)=1/2(10x+1)+5 equation: 



5(2x+1)=1/2(10x+1)+5

We move all terms to the left:

5(2x+1)-(1/2(10x+1)+5)=0



Domain of the equation: 2(10x+1)+5)!=0

x∈R



We multiply parentheses

10x-(1/2(10x+1)+5)+5=0

We multiply all the terms by the denominator


10x*2(10x+1)+5*2(10x+1)+5)-(1+5)=0

We add all the numbers together, and all the variables

10x*2(10x+1)+5*2(10x+1)+5)-6=0

We add all the numbers together, and all the variables

10x*2(10x+1)+5*2(10x+1)=0

Wy multiply elements

20x^2(1+10x(1=0

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