5(2x+1)=1/2(10x+1)+5

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Solution for 5(2x+1)=1/2(10x+1)+5 equation:



5(2x+1)=1/2(10x+1)+5
We move all terms to the left:
5(2x+1)-(1/2(10x+1)+5)=0
Domain of the equation: 2(10x+1)+5)!=0
x∈R
We multiply parentheses
10x-(1/2(10x+1)+5)+5=0
We multiply all the terms by the denominator
10x*2(10x+1)+5*2(10x+1)+5)-(1+5)=0
We add all the numbers together, and all the variables
10x*2(10x+1)+5*2(10x+1)+5)-6=0
We add all the numbers together, and all the variables
10x*2(10x+1)+5*2(10x+1)=0
Wy multiply elements
20x^2(1+10x(1=0

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