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5(2x+1)=131
We move all terms to the left:
5(2x+1)-(131)=0
We multiply parentheses
10x+5-131=0
We add all the numbers together, and all the variables
10x-126=0
We move all terms containing x to the left, all other terms to the right
10x=126
x=126/10
x=12+3/5
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