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5(2x+1)=3(2-x)
We move all terms to the left:
5(2x+1)-(3(2-x))=0
We add all the numbers together, and all the variables
5(2x+1)-(3(-1x+2))=0
We multiply parentheses
10x-(3(-1x+2))+5=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
10x+3x-6+5=0
We add all the numbers together, and all the variables
13x-1=0
We move all terms containing x to the left, all other terms to the right
13x=1
x=1/13
x=1/13
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