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5(2x+1)=3(3x-1)+10
We move all terms to the left:
5(2x+1)-(3(3x-1)+10)=0
We multiply parentheses
10x-(3(3x-1)+10)+5=0
We calculate terms in parentheses: -(3(3x-1)+10), so:We get rid of parentheses
3(3x-1)+10
We multiply parentheses
9x-3+10
We add all the numbers together, and all the variables
9x+7
Back to the equation:
-(9x+7)
10x-9x-7+5=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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