5(2x+1)=3(x+4)+-5

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Solution for 5(2x+1)=3(x+4)+-5 equation: 



5(2x+1)=3(x+4)+-5

We move all terms to the left:

5(2x+1)-(3(x+4)+-5)=0

We use the square of the difference formula

5(2x+1)-(3(x+4)-5)=0

We multiply parentheses

10x-(3(x+4)-5)+5=0



We calculate terms in parentheses: -(3(x+4)-5), so:

3(x+4)-5

We multiply parentheses

3x+12-5

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

10x-3x-7+5=0

We add all the numbers together, and all the variables

7x-2=0

We move all terms containing x to the left, all other terms to the right

7x=2

x=2/7

x=2/7

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