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5(2x+1)=3(x+4)-5.
We move all terms to the left:
5(2x+1)-(3(x+4)-5.)=0
We multiply parentheses
10x-(3(x+4)-5.)+5=0
We calculate terms in parentheses: -(3(x+4)-5.), so:We get rid of parentheses
3(x+4)-5.
We add all the numbers together, and all the variables
3(x+4)-5
We multiply parentheses
3x+12-5
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
10x-3x-7+5=0
We add all the numbers together, and all the variables
7x-2=0
We move all terms containing x to the left, all other terms to the right
7x=2
x=2/7
x=2/7
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