5(2x+1)=3(x+4)-5,x=

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Solution for 5(2x+1)=3(x+4)-5,x= equation: 



5(2x+1)=3(x+4)-5.x=

We move all terms to the left:

5(2x+1)-(3(x+4)-5.x)=0

We multiply parentheses

10x-(3(x+4)-5.x)+5=0



We calculate terms in parentheses: -(3(x+4)-5.x), so:

3(x+4)-5.x

We add all the numbers together, and all the variables

-5x+3(x+4)

We multiply parentheses

-5x+3x+12

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

10x+2x-12+5=0

We add all the numbers together, and all the variables

12x-7=0

We move all terms containing x to the left, all other terms to the right

12x=7

x=7/12

x=7/12

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