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5(2x+1)=3(x-10)
We move all terms to the left:
5(2x+1)-(3(x-10))=0
We multiply parentheses
10x-(3(x-10))+5=0
We calculate terms in parentheses: -(3(x-10)), so:We get rid of parentheses
3(x-10)
We multiply parentheses
3x-30
Back to the equation:
-(3x-30)
10x-3x+30+5=0
We add all the numbers together, and all the variables
7x+35=0
We move all terms containing x to the left, all other terms to the right
7x=-35
x=-35/7
x=-5
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