5(2x+1)=46+4(3x-2)

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Solution for 5(2x+1)=46+4(3x-2) equation: 



5(2x+1)=46+4(3x-2)

We move all terms to the left:

5(2x+1)-(46+4(3x-2))=0

We multiply parentheses

10x-(46+4(3x-2))+5=0



We calculate terms in parentheses: -(46+4(3x-2)), so:

46+4(3x-2)

determiningTheFunctionDomain
4(3x-2)+46

We multiply parentheses

12x-8+46

We add all the numbers together, and all the variables

12x+38

Back to the equation:

-(12x+38)



We get rid of parentheses

10x-12x-38+5=0

We add all the numbers together, and all the variables

-2x-33=0

We move all terms containing x to the left, all other terms to the right

-2x=33

x=33/-2

x=-16+1/2

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