5(2x+1)=4x+35

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Solution for 5(2x+1)=4x+35 equation: 



5(2x+1)=4x+35

We move all terms to the left:

5(2x+1)-(4x+35)=0

We multiply parentheses

10x-(4x+35)+5=0

We get rid of parentheses

10x-4x-35+5=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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