5(2x+1)=8x+41

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Solution for 5(2x+1)=8x+41 equation: 



5(2x+1)=8x+41

We move all terms to the left:

5(2x+1)-(8x+41)=0

We multiply parentheses

10x-(8x+41)+5=0

We get rid of parentheses

10x-8x-41+5=0

We add all the numbers together, and all the variables

2x-36=0

We move all terms containing x to the left, all other terms to the right

2x=36

x=36/2

x=18

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