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5(2x+2)=-4(4x-5)-3x
We move all terms to the left:
5(2x+2)-(-4(4x-5)-3x)=0
We multiply parentheses
10x-(-4(4x-5)-3x)+10=0
We calculate terms in parentheses: -(-4(4x-5)-3x), so:We get rid of parentheses
-4(4x-5)-3x
We add all the numbers together, and all the variables
-3x-4(4x-5)
We multiply parentheses
-3x-16x+20
We add all the numbers together, and all the variables
-19x+20
Back to the equation:
-(-19x+20)
10x+19x-20+10=0
We add all the numbers together, and all the variables
29x-10=0
We move all terms containing x to the left, all other terms to the right
29x=10
x=10/29
x=10/29
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