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5(2x+2)=2(x-11)
We move all terms to the left:
5(2x+2)-(2(x-11))=0
We multiply parentheses
10x-(2(x-11))+10=0
We calculate terms in parentheses: -(2(x-11)), so:We get rid of parentheses
2(x-11)
We multiply parentheses
2x-22
Back to the equation:
-(2x-22)
10x-2x+22+10=0
We add all the numbers together, and all the variables
8x+32=0
We move all terms containing x to the left, all other terms to the right
8x=-32
x=-32/8
x=-4
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