5(2x+2)=3(3x-2)

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Solution for 5(2x+2)=3(3x-2) equation: 



5(2x+2)=3(3x-2)

We move all terms to the left:

5(2x+2)-(3(3x-2))=0

We multiply parentheses

10x-(3(3x-2))+10=0



We calculate terms in parentheses: -(3(3x-2)), so:

3(3x-2)

We multiply parentheses

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

10x-9x+6+10=0

We add all the numbers together, and all the variables

x+16=0

We move all terms containing x to the left, all other terms to the right

x=-16

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