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5(2x+2)=5(2x+2)=20
We move all terms to the left:
5(2x+2)-(5(2x+2))=0
We multiply parentheses
10x-(5(2x+2))+10=0
We calculate terms in parentheses: -(5(2x+2)), so:We get rid of parentheses
5(2x+2)
We multiply parentheses
10x+10
Back to the equation:
-(10x+10)
10x-10x-10+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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