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5(2x+21)=3(x+35)
We move all terms to the left:
5(2x+21)-(3(x+35))=0
We multiply parentheses
10x-(3(x+35))+105=0
We calculate terms in parentheses: -(3(x+35)), so:We get rid of parentheses
3(x+35)
We multiply parentheses
3x+105
Back to the equation:
-(3x+105)
10x-3x-105+105=0
We add all the numbers together, and all the variables
7x=0
x=0/7
x=0
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