5(2x+3)+3(x-5)=4(2x+7)

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Solution for 5(2x+3)+3(x-5)=4(2x+7) equation: 



5(2x+3)+3(x-5)=4(2x+7)

We move all terms to the left:

5(2x+3)+3(x-5)-(4(2x+7))=0

We multiply parentheses

10x+3x-(4(2x+7))+15-15=0



We calculate terms in parentheses: -(4(2x+7)), so:

4(2x+7)

We multiply parentheses

8x+28

Back to the equation:

-(8x+28)



We add all the numbers together, and all the variables

13x-(8x+28)=0

We get rid of parentheses

13x-8x-28=0

We add all the numbers together, and all the variables

5x-28=0

We move all terms containing x to the left, all other terms to the right

5x=28

x=28/5

x=5+3/5

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