5(2x+3)+4(6x+6)+2=34x+41

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Solution for 5(2x+3)+4(6x+6)+2=34x+41 equation: 



5(2x+3)+4(6x+6)+2=34x+41

We move all terms to the left:

5(2x+3)+4(6x+6)+2-(34x+41)=0

We multiply parentheses

10x+24x-(34x+41)+15+24+2=0

We get rid of parentheses

10x+24x-34x-41+15+24+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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