5(2x+3)+4x+2=7(x+1)+20+2x

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Solution for 5(2x+3)+4x+2=7(x+1)+20+2x equation: 



5(2x+3)+4x+2=7(x+1)+20+2x

We move all terms to the left:

5(2x+3)+4x+2-(7(x+1)+20+2x)=0

We add all the numbers together, and all the variables

4x+5(2x+3)-(7(x+1)+20+2x)+2=0

We multiply parentheses

4x+10x-(7(x+1)+20+2x)+15+2=0



We calculate terms in parentheses: -(7(x+1)+20+2x), so:

7(x+1)+20+2x

determiningTheFunctionDomain
7(x+1)+2x+20

We add all the numbers together, and all the variables

2x+7(x+1)+20

We multiply parentheses

2x+7x+7+20

We add all the numbers together, and all the variables

9x+27

Back to the equation:

-(9x+27)



We add all the numbers together, and all the variables

14x-(9x+27)+17=0

We get rid of parentheses

14x-9x-27+17=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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