5(2x+3)+4x=7(2x+1)+8

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Solution for 5(2x+3)+4x=7(2x+1)+8 equation: 



5(2x+3)+4x=7(2x+1)+8

We move all terms to the left:

5(2x+3)+4x-(7(2x+1)+8)=0

We add all the numbers together, and all the variables

4x+5(2x+3)-(7(2x+1)+8)=0

We multiply parentheses

4x+10x-(7(2x+1)+8)+15=0



We calculate terms in parentheses: -(7(2x+1)+8), so:

7(2x+1)+8

We multiply parentheses

14x+7+8

We add all the numbers together, and all the variables

14x+15

Back to the equation:

-(14x+15)



We add all the numbers together, and all the variables

14x-(14x+15)+15=0

We get rid of parentheses

14x-14x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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