5(2x+3)-12(6-x)=11(4x+7)

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Solution for 5(2x+3)-12(6-x)=11(4x+7) equation: 



5(2x+3)-12(6-x)=11(4x+7)

We move all terms to the left:

5(2x+3)-12(6-x)-(11(4x+7))=0

We add all the numbers together, and all the variables

5(2x+3)-12(-1x+6)-(11(4x+7))=0

We multiply parentheses

10x+12x-(11(4x+7))+15-72=0



We calculate terms in parentheses: -(11(4x+7)), so:

11(4x+7)

We multiply parentheses

44x+77

Back to the equation:

-(44x+77)



We add all the numbers together, and all the variables

22x-(44x+77)-57=0

We get rid of parentheses

22x-44x-77-57=0

We add all the numbers together, and all the variables

-22x-134=0

We move all terms containing x to the left, all other terms to the right

-22x=134

x=134/-22

x=-6+1/11

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