5(2x+3)-12(6-x)=11(4x+7)+86

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Solution for 5(2x+3)-12(6-x)=11(4x+7)+86 equation:



5(2x+3)-12(6-x)=11(4x+7)+86
We move all terms to the left:
5(2x+3)-12(6-x)-(11(4x+7)+86)=0
We add all the numbers together, and all the variables
5(2x+3)-12(-1x+6)-(11(4x+7)+86)=0
We multiply parentheses
10x+12x-(11(4x+7)+86)+15-72=0
We calculate terms in parentheses: -(11(4x+7)+86), so:
11(4x+7)+86
We multiply parentheses
44x+77+86
We add all the numbers together, and all the variables
44x+163
Back to the equation:
-(44x+163)
We add all the numbers together, and all the variables
22x-(44x+163)-57=0
We get rid of parentheses
22x-44x-163-57=0
We add all the numbers together, and all the variables
-22x-220=0
We move all terms containing x to the left, all other terms to the right
-22x=220
x=220/-22
x=-10

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