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5(2x+3)-4=3(3x-1)+x
We move all terms to the left:
5(2x+3)-4-(3(3x-1)+x)=0
We multiply parentheses
10x-(3(3x-1)+x)+15-4=0
We calculate terms in parentheses: -(3(3x-1)+x), so:We add all the numbers together, and all the variables
3(3x-1)+x
We add all the numbers together, and all the variables
x+3(3x-1)
We multiply parentheses
x+9x-3
We add all the numbers together, and all the variables
10x-3
Back to the equation:
-(10x-3)
10x-(10x-3)+11=0
We get rid of parentheses
10x-10x+3+11=0
We add all the numbers together, and all the variables
14!=0
There is no solution for this equation
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