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5(2x+3)-6(x-5)=35
We move all terms to the left:
5(2x+3)-6(x-5)-(35)=0
We multiply parentheses
10x-6x+15+30-35=0
We add all the numbers together, and all the variables
4x+10=0
We move all terms containing x to the left, all other terms to the right
4x=-10
x=-10/4
x=-2+1/2
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