5(2x+3)-7x+45=15(2x-4)-7x

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Solution for 5(2x+3)-7x+45=15(2x-4)-7x equation: 



5(2x+3)-7x+45=15(2x-4)-7x

We move all terms to the left:

5(2x+3)-7x+45-(15(2x-4)-7x)=0

We add all the numbers together, and all the variables

-7x+5(2x+3)-(15(2x-4)-7x)+45=0

We multiply parentheses

-7x+10x-(15(2x-4)-7x)+15+45=0



We calculate terms in parentheses: -(15(2x-4)-7x), so:

15(2x-4)-7x

We add all the numbers together, and all the variables

-7x+15(2x-4)

We multiply parentheses

-7x+30x-60

We add all the numbers together, and all the variables

23x-60

Back to the equation:

-(23x-60)



We add all the numbers together, and all the variables

3x-(23x-60)+60=0

We get rid of parentheses

3x-23x+60+60=0

We add all the numbers together, and all the variables

-20x+120=0

We move all terms containing x to the left, all other terms to the right

-20x=-120

x=-120/-20

x=+6

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