5(2x+3)=-2(x-10)+31

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Solution for 5(2x+3)=-2(x-10)+31 equation: 



5(2x+3)=-2(x-10)+31

We move all terms to the left:

5(2x+3)-(-2(x-10)+31)=0

We multiply parentheses

10x-(-2(x-10)+31)+15=0



We calculate terms in parentheses: -(-2(x-10)+31), so:

-2(x-10)+31

We multiply parentheses

-2x+20+31

We add all the numbers together, and all the variables

-2x+51

Back to the equation:

-(-2x+51)



We get rid of parentheses

10x+2x-51+15=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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