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5(2x+3)=-5(2x-4)-2x
We move all terms to the left:
5(2x+3)-(-5(2x-4)-2x)=0
We multiply parentheses
10x-(-5(2x-4)-2x)+15=0
We calculate terms in parentheses: -(-5(2x-4)-2x), so:We get rid of parentheses
-5(2x-4)-2x
We add all the numbers together, and all the variables
-2x-5(2x-4)
We multiply parentheses
-2x-10x+20
We add all the numbers together, and all the variables
-12x+20
Back to the equation:
-(-12x+20)
10x+12x-20+15=0
We add all the numbers together, and all the variables
22x-5=0
We move all terms containing x to the left, all other terms to the right
22x=5
x=5/22
x=5/22
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