5(2x+3)=2(x-4)=31

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Solution for 5(2x+3)=2(x-4)=31 equation: 



5(2x+3)=2(x-4)=31

We move all terms to the left:

5(2x+3)-(2(x-4))=0

We multiply parentheses

10x-(2(x-4))+15=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

10x-2x+8+15=0

We add all the numbers together, and all the variables

8x+23=0

We move all terms containing x to the left, all other terms to the right

8x=-23

x=-23/8

x=-2+7/8

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