5(2x+3)=3(2x-4)+6

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Solution for 5(2x+3)=3(2x-4)+6 equation: 



5(2x+3)=3(2x-4)+6

We move all terms to the left:

5(2x+3)-(3(2x-4)+6)=0

We multiply parentheses

10x-(3(2x-4)+6)+15=0



We calculate terms in parentheses: -(3(2x-4)+6), so:

3(2x-4)+6

We multiply parentheses

6x-12+6

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We get rid of parentheses

10x-6x+6+15=0

We add all the numbers together, and all the variables

4x+21=0

We move all terms containing x to the left, all other terms to the right

4x=-21

x=-21/4

x=-5+1/4

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