5(2x+3)=3(3x+12)=

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Solution for 5(2x+3)=3(3x+12)= equation: 



5(2x+3)=3(3x+12)=

We move all terms to the left:

5(2x+3)-(3(3x+12))=0

We multiply parentheses

10x-(3(3x+12))+15=0



We calculate terms in parentheses: -(3(3x+12)), so:

3(3x+12)

We multiply parentheses

9x+36

Back to the equation:

-(9x+36)



We get rid of parentheses

10x-9x-36+15=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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